\(\int \frac {\cos ^2(c+d x) (B \sec (c+d x)+C \sec ^2(c+d x))}{(a+b \sec (c+d x))^3} \, dx\) [813]

Optimal result

Integrand size = 40, antiderivative size = 290 \[ \int \frac {\cos ^2(c+d x) \left (B \sec (c+d x)+C \sec ^2(c+d x)\right )}{(a+b \sec (c+d x))^3} \, dx=-\frac {(3 b B-a C) x}{a^4}+\frac {b \left (12 a^4 b B-15 a^2 b^3 B+6 b^5 B-6 a^5 C+5 a^3 b^2 C-2 a b^4 C\right ) \text {arctanh}\left (\frac {\sqrt {a-b} \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a+b}}\right )}{a^4 (a-b)^{5/2} (a+b)^{5/2} d}+\frac {\left (2 a^4 B-11 a^2 b^2 B+6 b^4 B+5 a^3 b C-2 a b^3 C\right ) \sin (c+d x)}{2 a^3 \left (a^2-b^2\right )^2 d}+\frac {b (b B-a C) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {b \left (6 a^2 b B-3 b^3 B-4 a^3 C+a b^2 C\right ) \sin (c+d x)}{2 a^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))} \]

[Out]

-(3*B*b-C*a)*x/a^4+b*(12*B*a^4*b-15*B*a^2*b^3+6*B*b^5-6*C*a^5+5*C*a^3*b^2-2*C*a*b^4)*arctanh((a-b)^(1/2)*tan(1
/2*d*x+1/2*c)/(a+b)^(1/2))/a^4/(a-b)^(5/2)/(a+b)^(5/2)/d+1/2*(2*B*a^4-11*B*a^2*b^2+6*B*b^4+5*C*a^3*b-2*C*a*b^3
)*sin(d*x+c)/a^3/(a^2-b^2)^2/d+1/2*b*(B*b-C*a)*sin(d*x+c)/a/(a^2-b^2)/d/(a+b*sec(d*x+c))^2+1/2*b*(6*B*a^2*b-3*
B*b^3-4*C*a^3+C*a*b^2)*sin(d*x+c)/a^2/(a^2-b^2)^2/d/(a+b*sec(d*x+c))

Rubi [A] (verified)

Time = 1.70 (sec) , antiderivative size = 290, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {4157, 4115, 4185, 4189, 4004, 3916, 2738, 214} \[ \int \frac {\cos ^2(c+d x) \left (B \sec (c+d x)+C \sec ^2(c+d x)\right )}{(a+b \sec (c+d x))^3} \, dx=-\frac {x (3 b B-a C)}{a^4}+\frac {b (b B-a C) \sin (c+d x)}{2 a d \left (a^2-b^2\right ) (a+b \sec (c+d x))^2}+\frac {b \left (-4 a^3 C+6 a^2 b B+a b^2 C-3 b^3 B\right ) \sin (c+d x)}{2 a^2 d \left (a^2-b^2\right )^2 (a+b \sec (c+d x))}+\frac {\left (2 a^4 B+5 a^3 b C-11 a^2 b^2 B-2 a b^3 C+6 b^4 B\right ) \sin (c+d x)}{2 a^3 d \left (a^2-b^2\right )^2}+\frac {b \left (-6 a^5 C+12 a^4 b B+5 a^3 b^2 C-15 a^2 b^3 B-2 a b^4 C+6 b^5 B\right ) \text {arctanh}\left (\frac {\sqrt {a-b} \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a+b}}\right )}{a^4 d (a-b)^{5/2} (a+b)^{5/2}} \]

[In]

Int[(Cos[c + d*x]^2*(B*Sec[c + d*x] + C*Sec[c + d*x]^2))/(a + b*Sec[c + d*x])^3,x]

[Out]

-(((3*b*B - a*C)*x)/a^4) + (b*(12*a^4*b*B - 15*a^2*b^3*B + 6*b^5*B - 6*a^5*C + 5*a^3*b^2*C - 2*a*b^4*C)*ArcTan
h[(Sqrt[a - b]*Tan[(c + d*x)/2])/Sqrt[a + b]])/(a^4*(a - b)^(5/2)*(a + b)^(5/2)*d) + ((2*a^4*B - 11*a^2*b^2*B
+ 6*b^4*B + 5*a^3*b*C - 2*a*b^3*C)*Sin[c + d*x])/(2*a^3*(a^2 - b^2)^2*d) + (b*(b*B - a*C)*Sin[c + d*x])/(2*a*(
a^2 - b^2)*d*(a + b*Sec[c + d*x])^2) + (b*(6*a^2*b*B - 3*b^3*B - 4*a^3*C + a*b^2*C)*Sin[c + d*x])/(2*a^2*(a^2
- b^2)^2*d*(a + b*Sec[c + d*x]))

Rule 214

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x/Rt[-a/b, 2]], x] /; FreeQ[{a, b},
x] && NegQ[a/b]

Rule 2738

Int[((a_) + (b_.)*sin[Pi/2 + (c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> With[{e = FreeFactors[Tan[(c + d*x)/2], x
]}, Dist[2*(e/d), Subst[Int[1/(a + b + (a - b)*e^2*x^2), x], x, Tan[(c + d*x)/2]/e], x]] /; FreeQ[{a, b, c, d}
, x] && NeQ[a^2 - b^2, 0]

Rule 3916

Int[csc[(e_.) + (f_.)*(x_)]/(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)), x_Symbol] :> Dist[1/b, Int[1/(1 + (a/b)*Si
n[e + f*x]), x], x] /; FreeQ[{a, b, e, f}, x] && NeQ[a^2 - b^2, 0]

Rule 4004

Int[(csc[(e_.) + (f_.)*(x_)]*(d_.) + (c_))/(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)), x_Symbol] :> Simp[c*(x/a),
x] - Dist[(b*c - a*d)/a, Int[Csc[e + f*x]/(a + b*Csc[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[
b*c - a*d, 0]

Rule 4115

Int[(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_)*(csc[(e_.) + (f_.)*(x_)]*
(B_.) + (A_)), x_Symbol] :> Simp[b*(A*b - a*B)*Cot[e + f*x]*(a + b*Csc[e + f*x])^(m + 1)*((d*Csc[e + f*x])^n/(
a*f*(m + 1)*(a^2 - b^2))), x] + Dist[1/(a*(m + 1)*(a^2 - b^2)), Int[(a + b*Csc[e + f*x])^(m + 1)*(d*Csc[e + f*
x])^n*Simp[A*(a^2*(m + 1) - b^2*(m + n + 1)) + a*b*B*n - a*(A*b - a*B)*(m + 1)*Csc[e + f*x] + b*(A*b - a*B)*(m
+ n + 2)*Csc[e + f*x]^2, x], x], x] /; FreeQ[{a, b, d, e, f, A, B, n}, x] && NeQ[A*b - a*B, 0] && NeQ[a^2 - b
^2, 0] && LtQ[m, -1] &&  !(ILtQ[m + 1/2, 0] && ILtQ[n, 0])

Rule 4157

Int[((a_.) + csc[(e_.) + (f_.)*(x_)]*(b_.))^(m_.)*((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(
x_)]^2*(C_.))*((c_.) + csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_.), x_Symbol] :> Dist[1/b^2, Int[(a + b*Csc[e + f*x])
^(m + 1)*(c + d*Csc[e + f*x])^n*(b*B - a*C + b*C*Csc[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C, m,
n}, x] && EqQ[A*b^2 - a*b*B + a^2*C, 0]

Rule 4185

Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_.))*(csc[(e_.) + (f_.)*(x_)]*(d_.))^
(n_)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_), x_Symbol] :> Simp[(A*b^2 - a*b*B + a^2*C)*Cot[e + f*x]*(a +
b*Csc[e + f*x])^(m + 1)*((d*Csc[e + f*x])^n/(a*f*(m + 1)*(a^2 - b^2))), x] + Dist[1/(a*(m + 1)*(a^2 - b^2)), I
nt[(a + b*Csc[e + f*x])^(m + 1)*(d*Csc[e + f*x])^n*Simp[a*(a*A - b*B + a*C)*(m + 1) - (A*b^2 - a*b*B + a^2*C)*
(m + n + 1) - a*(A*b - a*B + b*C)*(m + 1)*Csc[e + f*x] + (A*b^2 - a*b*B + a^2*C)*(m + n + 2)*Csc[e + f*x]^2, x
], x], x] /; FreeQ[{a, b, d, e, f, A, B, C, n}, x] && NeQ[a^2 - b^2, 0] && LtQ[m, -1] &&  !(ILtQ[m + 1/2, 0] &
& ILtQ[n, 0])

Rule 4189

Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_.))*(csc[(e_.) + (f_.)*(x_)]*(d_.))^
(n_)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_), x_Symbol] :> Simp[A*Cot[e + f*x]*(a + b*Csc[e + f*x])^(m + 1
)*((d*Csc[e + f*x])^n/(a*f*n)), x] + Dist[1/(a*d*n), Int[(a + b*Csc[e + f*x])^m*(d*Csc[e + f*x])^(n + 1)*Simp[
a*B*n - A*b*(m + n + 1) + a*(A + A*n + C*n)*Csc[e + f*x] + A*b*(m + n + 2)*Csc[e + f*x]^2, x], x], x] /; FreeQ
[{a, b, d, e, f, A, B, C, m}, x] && NeQ[a^2 - b^2, 0] && LeQ[n, -1]

Rubi steps \begin{align*} \text {integral}& = \int \frac {\cos (c+d x) (B+C \sec (c+d x))}{(a+b \sec (c+d x))^3} \, dx \\ & = \frac {b (b B-a C) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}-\frac {\int \frac {\cos (c+d x) \left (-2 a^2 B+3 b^2 B-a b C+2 a (b B-a C) \sec (c+d x)-2 b (b B-a C) \sec ^2(c+d x)\right )}{(a+b \sec (c+d x))^2} \, dx}{2 a \left (a^2-b^2\right )} \\ & = \frac {b (b B-a C) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {b \left (6 a^2 b B-3 b^3 B-4 a^3 C+a b^2 C\right ) \sin (c+d x)}{2 a^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))}+\frac {\int \frac {\cos (c+d x) \left (2 a^4 B-11 a^2 b^2 B+6 b^4 B+5 a^3 b C-2 a b^3 C-a \left (4 a^2 b B-b^3 B-2 a^3 C-a b^2 C\right ) \sec (c+d x)+b \left (6 a^2 b B-3 b^3 B-4 a^3 C+a b^2 C\right ) \sec ^2(c+d x)\right )}{a+b \sec (c+d x)} \, dx}{2 a^2 \left (a^2-b^2\right )^2} \\ & = \frac {\left (2 a^4 B-11 a^2 b^2 B+6 b^4 B+5 a^3 b C-2 a b^3 C\right ) \sin (c+d x)}{2 a^3 \left (a^2-b^2\right )^2 d}+\frac {b (b B-a C) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {b \left (6 a^2 b B-3 b^3 B-4 a^3 C+a b^2 C\right ) \sin (c+d x)}{2 a^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))}-\frac {\int \frac {2 \left (a^2-b^2\right )^2 (3 b B-a C)-a b \left (6 a^2 b B-3 b^3 B-4 a^3 C+a b^2 C\right ) \sec (c+d x)}{a+b \sec (c+d x)} \, dx}{2 a^3 \left (a^2-b^2\right )^2} \\ & = -\frac {(3 b B-a C) x}{a^4}+\frac {\left (2 a^4 B-11 a^2 b^2 B+6 b^4 B+5 a^3 b C-2 a b^3 C\right ) \sin (c+d x)}{2 a^3 \left (a^2-b^2\right )^2 d}+\frac {b (b B-a C) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {b \left (6 a^2 b B-3 b^3 B-4 a^3 C+a b^2 C\right ) \sin (c+d x)}{2 a^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))}+\frac {\left (b \left (12 a^4 b B-15 a^2 b^3 B+6 b^5 B-6 a^5 C+5 a^3 b^2 C-2 a b^4 C\right )\right ) \int \frac {\sec (c+d x)}{a+b \sec (c+d x)} \, dx}{2 a^4 \left (a^2-b^2\right )^2} \\ & = -\frac {(3 b B-a C) x}{a^4}+\frac {\left (2 a^4 B-11 a^2 b^2 B+6 b^4 B+5 a^3 b C-2 a b^3 C\right ) \sin (c+d x)}{2 a^3 \left (a^2-b^2\right )^2 d}+\frac {b (b B-a C) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {b \left (6 a^2 b B-3 b^3 B-4 a^3 C+a b^2 C\right ) \sin (c+d x)}{2 a^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))}+\frac {\left (12 a^4 b B-15 a^2 b^3 B+6 b^5 B-6 a^5 C+5 a^3 b^2 C-2 a b^4 C\right ) \int \frac {1}{1+\frac {a \cos (c+d x)}{b}} \, dx}{2 a^4 \left (a^2-b^2\right )^2} \\ & = -\frac {(3 b B-a C) x}{a^4}+\frac {\left (2 a^4 B-11 a^2 b^2 B+6 b^4 B+5 a^3 b C-2 a b^3 C\right ) \sin (c+d x)}{2 a^3 \left (a^2-b^2\right )^2 d}+\frac {b (b B-a C) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {b \left (6 a^2 b B-3 b^3 B-4 a^3 C+a b^2 C\right ) \sin (c+d x)}{2 a^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))}+\frac {\left (12 a^4 b B-15 a^2 b^3 B+6 b^5 B-6 a^5 C+5 a^3 b^2 C-2 a b^4 C\right ) \text {Subst}\left (\int \frac {1}{1+\frac {a}{b}+\left (1-\frac {a}{b}\right ) x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{a^4 \left (a^2-b^2\right )^2 d} \\ & = -\frac {(3 b B-a C) x}{a^4}+\frac {b \left (12 a^4 b B-15 a^2 b^3 B+6 b^5 B-6 a^5 C+5 a^3 b^2 C-2 a b^4 C\right ) \text {arctanh}\left (\frac {\sqrt {a-b} \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a+b}}\right )}{a^4 (a-b)^{5/2} (a+b)^{5/2} d}+\frac {\left (2 a^4 B-11 a^2 b^2 B+6 b^4 B+5 a^3 b C-2 a b^3 C\right ) \sin (c+d x)}{2 a^3 \left (a^2-b^2\right )^2 d}+\frac {b (b B-a C) \sin (c+d x)}{2 a \left (a^2-b^2\right ) d (a+b \sec (c+d x))^2}+\frac {b \left (6 a^2 b B-3 b^3 B-4 a^3 C+a b^2 C\right ) \sin (c+d x)}{2 a^2 \left (a^2-b^2\right )^2 d (a+b \sec (c+d x))} \\ \end{align*}

Mathematica [A] (verified)

Time = 2.37 (sec) , antiderivative size = 232, normalized size of antiderivative = 0.80 \[ \int \frac {\cos ^2(c+d x) \left (B \sec (c+d x)+C \sec ^2(c+d x)\right )}{(a+b \sec (c+d x))^3} \, dx=\frac {2 (-3 b B+a C) (c+d x)-\frac {2 b \left (12 a^4 b B-15 a^2 b^3 B+6 b^5 B-6 a^5 C+5 a^3 b^2 C-2 a b^4 C\right ) \text {arctanh}\left (\frac {(-a+b) \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{\left (a^2-b^2\right )^{5/2}}+2 a B \sin (c+d x)+\frac {a b^3 (b B-a C) \sin (c+d x)}{(a-b) (a+b) (b+a \cos (c+d x))^2}+\frac {a b^2 \left (-8 a^2 b B+5 b^3 B+6 a^3 C-3 a b^2 C\right ) \sin (c+d x)}{(a-b)^2 (a+b)^2 (b+a \cos (c+d x))}}{2 a^4 d} \]

[In]

Integrate[(Cos[c + d*x]^2*(B*Sec[c + d*x] + C*Sec[c + d*x]^2))/(a + b*Sec[c + d*x])^3,x]

[Out]

(2*(-3*b*B + a*C)*(c + d*x) - (2*b*(12*a^4*b*B - 15*a^2*b^3*B + 6*b^5*B - 6*a^5*C + 5*a^3*b^2*C - 2*a*b^4*C)*A
rcTanh[((-a + b)*Tan[(c + d*x)/2])/Sqrt[a^2 - b^2]])/(a^2 - b^2)^(5/2) + 2*a*B*Sin[c + d*x] + (a*b^3*(b*B - a*
C)*Sin[c + d*x])/((a - b)*(a + b)*(b + a*Cos[c + d*x])^2) + (a*b^2*(-8*a^2*b*B + 5*b^3*B + 6*a^3*C - 3*a*b^2*C
)*Sin[c + d*x])/((a - b)^2*(a + b)^2*(b + a*Cos[c + d*x])))/(2*a^4*d)

Maple [A] (verified)

Time = 0.80 (sec) , antiderivative size = 347, normalized size of antiderivative = 1.20

method	result	size
derivativedivides	\(\frac {-\frac {2 \left (-\frac {B a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}+\left (3 B b -C a \right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )}{a^{4}}-\frac {2 b \left (\frac {-\frac {\left (8 B \,a^{2} b +B a \,b^{2}-4 B \,b^{3}-6 a^{3} C -a^{2} b C +2 C a \,b^{2}\right ) a b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{2 \left (a -b \right ) \left (a^{2}+2 a b +b^{2}\right )}+\frac {b a \left (8 B \,a^{2} b -B a \,b^{2}-4 B \,b^{3}-6 a^{3} C +a^{2} b C +2 C a \,b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2 \left (a +b \right ) \left (a -b \right )^{2}}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} b -a -b \right )^{2}}-\frac {\left (12 B \,a^{4} b -15 B \,a^{2} b^{3}+6 B \,b^{5}-6 a^{5} C +5 C \,a^{3} b^{2}-2 C a \,b^{4}\right ) \operatorname {arctanh}\left (\frac {\left (a -b \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{\sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{2 \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{a^{4}}}{d}\)	\(347\)
default	\(\frac {-\frac {2 \left (-\frac {B a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}+\left (3 B b -C a \right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )}{a^{4}}-\frac {2 b \left (\frac {-\frac {\left (8 B \,a^{2} b +B a \,b^{2}-4 B \,b^{3}-6 a^{3} C -a^{2} b C +2 C a \,b^{2}\right ) a b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{2 \left (a -b \right ) \left (a^{2}+2 a b +b^{2}\right )}+\frac {b a \left (8 B \,a^{2} b -B a \,b^{2}-4 B \,b^{3}-6 a^{3} C +a^{2} b C +2 C a \,b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2 \left (a +b \right ) \left (a -b \right )^{2}}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} b -a -b \right )^{2}}-\frac {\left (12 B \,a^{4} b -15 B \,a^{2} b^{3}+6 B \,b^{5}-6 a^{5} C +5 C \,a^{3} b^{2}-2 C a \,b^{4}\right ) \operatorname {arctanh}\left (\frac {\left (a -b \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{\sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{2 \left (a^{4}-2 a^{2} b^{2}+b^{4}\right ) \sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{a^{4}}}{d}\)	\(347\)
risch	\(\text {Expression too large to display}\)	\(1399\)

[In]

int(cos(d*x+c)^2*(B*sec(d*x+c)+C*sec(d*x+c)^2)/(a+b*sec(d*x+c))^3,x,method=_RETURNVERBOSE)

[Out]

1/d*(-2/a^4*(-B*a*tan(1/2*d*x+1/2*c)/(1+tan(1/2*d*x+1/2*c)^2)+(3*B*b-C*a)*arctan(tan(1/2*d*x+1/2*c)))-2*b/a^4*
((-1/2*(8*B*a^2*b+B*a*b^2-4*B*b^3-6*C*a^3-C*a^2*b+2*C*a*b^2)*a*b/(a-b)/(a^2+2*a*b+b^2)*tan(1/2*d*x+1/2*c)^3+1/
2*b*a*(8*B*a^2*b-B*a*b^2-4*B*b^3-6*C*a^3+C*a^2*b+2*C*a*b^2)/(a+b)/(a-b)^2*tan(1/2*d*x+1/2*c))/(tan(1/2*d*x+1/2
*c)^2*a-tan(1/2*d*x+1/2*c)^2*b-a-b)^2-1/2*(12*B*a^4*b-15*B*a^2*b^3+6*B*b^5-6*C*a^5+5*C*a^3*b^2-2*C*a*b^4)/(a^4
-2*a^2*b^2+b^4)/((a+b)*(a-b))^(1/2)*arctanh((a-b)*tan(1/2*d*x+1/2*c)/((a+b)*(a-b))^(1/2))))

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 755 vs. \(2 (275) = 550\).

Time = 0.37 (sec) , antiderivative size = 1568, normalized size of antiderivative = 5.41 \[ \int \frac {\cos ^2(c+d x) \left (B \sec (c+d x)+C \sec ^2(c+d x)\right )}{(a+b \sec (c+d x))^3} \, dx=\text {Too large to display} \]

[In]

integrate(cos(d*x+c)^2*(B*sec(d*x+c)+C*sec(d*x+c)^2)/(a+b*sec(d*x+c))^3,x, algorithm="fricas")

[Out]

[1/4*(4*(C*a^9 - 3*B*a^8*b - 3*C*a^7*b^2 + 9*B*a^6*b^3 + 3*C*a^5*b^4 - 9*B*a^4*b^5 - C*a^3*b^6 + 3*B*a^2*b^7)*
d*x*cos(d*x + c)^2 + 8*(C*a^8*b - 3*B*a^7*b^2 - 3*C*a^6*b^3 + 9*B*a^5*b^4 + 3*C*a^4*b^5 - 9*B*a^3*b^6 - C*a^2*
b^7 + 3*B*a*b^8)*d*x*cos(d*x + c) + 4*(C*a^7*b^2 - 3*B*a^6*b^3 - 3*C*a^5*b^4 + 9*B*a^4*b^5 + 3*C*a^3*b^6 - 9*B
*a^2*b^7 - C*a*b^8 + 3*B*b^9)*d*x - (6*C*a^5*b^3 - 12*B*a^4*b^4 - 5*C*a^3*b^5 + 15*B*a^2*b^6 + 2*C*a*b^7 - 6*B
*b^8 + (6*C*a^7*b - 12*B*a^6*b^2 - 5*C*a^5*b^3 + 15*B*a^4*b^4 + 2*C*a^3*b^5 - 6*B*a^2*b^6)*cos(d*x + c)^2 + 2*
(6*C*a^6*b^2 - 12*B*a^5*b^3 - 5*C*a^4*b^4 + 15*B*a^3*b^5 + 2*C*a^2*b^6 - 6*B*a*b^7)*cos(d*x + c))*sqrt(a^2 - b
^2)*log((2*a*b*cos(d*x + c) - (a^2 - 2*b^2)*cos(d*x + c)^2 + 2*sqrt(a^2 - b^2)*(b*cos(d*x + c) + a)*sin(d*x +
c) + 2*a^2 - b^2)/(a^2*cos(d*x + c)^2 + 2*a*b*cos(d*x + c) + b^2)) + 2*(2*B*a^7*b^2 + 5*C*a^6*b^3 - 13*B*a^5*b
^4 - 7*C*a^4*b^5 + 17*B*a^3*b^6 + 2*C*a^2*b^7 - 6*B*a*b^8 + 2*(B*a^9 - 3*B*a^7*b^2 + 3*B*a^5*b^4 - B*a^3*b^6)*
cos(d*x + c)^2 + (4*B*a^8*b + 6*C*a^7*b^2 - 20*B*a^6*b^3 - 9*C*a^5*b^4 + 25*B*a^4*b^5 + 3*C*a^3*b^6 - 9*B*a^2*
b^7)*cos(d*x + c))*sin(d*x + c))/((a^12 - 3*a^10*b^2 + 3*a^8*b^4 - a^6*b^6)*d*cos(d*x + c)^2 + 2*(a^11*b - 3*a
^9*b^3 + 3*a^7*b^5 - a^5*b^7)*d*cos(d*x + c) + (a^10*b^2 - 3*a^8*b^4 + 3*a^6*b^6 - a^4*b^8)*d), 1/2*(2*(C*a^9
- 3*B*a^8*b - 3*C*a^7*b^2 + 9*B*a^6*b^3 + 3*C*a^5*b^4 - 9*B*a^4*b^5 - C*a^3*b^6 + 3*B*a^2*b^7)*d*x*cos(d*x + c
)^2 + 4*(C*a^8*b - 3*B*a^7*b^2 - 3*C*a^6*b^3 + 9*B*a^5*b^4 + 3*C*a^4*b^5 - 9*B*a^3*b^6 - C*a^2*b^7 + 3*B*a*b^8
)*d*x*cos(d*x + c) + 2*(C*a^7*b^2 - 3*B*a^6*b^3 - 3*C*a^5*b^4 + 9*B*a^4*b^5 + 3*C*a^3*b^6 - 9*B*a^2*b^7 - C*a*
b^8 + 3*B*b^9)*d*x - (6*C*a^5*b^3 - 12*B*a^4*b^4 - 5*C*a^3*b^5 + 15*B*a^2*b^6 + 2*C*a*b^7 - 6*B*b^8 + (6*C*a^7
*b - 12*B*a^6*b^2 - 5*C*a^5*b^3 + 15*B*a^4*b^4 + 2*C*a^3*b^5 - 6*B*a^2*b^6)*cos(d*x + c)^2 + 2*(6*C*a^6*b^2 -
12*B*a^5*b^3 - 5*C*a^4*b^4 + 15*B*a^3*b^5 + 2*C*a^2*b^6 - 6*B*a*b^7)*cos(d*x + c))*sqrt(-a^2 + b^2)*arctan(-sq
rt(-a^2 + b^2)*(b*cos(d*x + c) + a)/((a^2 - b^2)*sin(d*x + c))) + (2*B*a^7*b^2 + 5*C*a^6*b^3 - 13*B*a^5*b^4 -
7*C*a^4*b^5 + 17*B*a^3*b^6 + 2*C*a^2*b^7 - 6*B*a*b^8 + 2*(B*a^9 - 3*B*a^7*b^2 + 3*B*a^5*b^4 - B*a^3*b^6)*cos(d
*x + c)^2 + (4*B*a^8*b + 6*C*a^7*b^2 - 20*B*a^6*b^3 - 9*C*a^5*b^4 + 25*B*a^4*b^5 + 3*C*a^3*b^6 - 9*B*a^2*b^7)*
cos(d*x + c))*sin(d*x + c))/((a^12 - 3*a^10*b^2 + 3*a^8*b^4 - a^6*b^6)*d*cos(d*x + c)^2 + 2*(a^11*b - 3*a^9*b^
3 + 3*a^7*b^5 - a^5*b^7)*d*cos(d*x + c) + (a^10*b^2 - 3*a^8*b^4 + 3*a^6*b^6 - a^4*b^8)*d)]

Sympy [F]

\[ \int \frac {\cos ^2(c+d x) \left (B \sec (c+d x)+C \sec ^2(c+d x)\right )}{(a+b \sec (c+d x))^3} \, dx=\int \frac {\left (B + C \sec {\left (c + d x \right )}\right ) \cos ^{2}{\left (c + d x \right )} \sec {\left (c + d x \right )}}{\left (a + b \sec {\left (c + d x \right )}\right )^{3}}\, dx \]

[In]

integrate(cos(d*x+c)**2*(B*sec(d*x+c)+C*sec(d*x+c)**2)/(a+b*sec(d*x+c))**3,x)

[Out]

Integral((B + C*sec(c + d*x))*cos(c + d*x)**2*sec(c + d*x)/(a + b*sec(c + d*x))**3, x)

Maxima [F(-2)]

Exception generated. \[ \int \frac {\cos ^2(c+d x) \left (B \sec (c+d x)+C \sec ^2(c+d x)\right )}{(a+b \sec (c+d x))^3} \, dx=\text {Exception raised: ValueError} \]

[In]

integrate(cos(d*x+c)^2*(B*sec(d*x+c)+C*sec(d*x+c)^2)/(a+b*sec(d*x+c))^3,x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(4*a^2-4*b^2>0)', see `assume?`
for more de

Giac [A] (verification not implemented)

none

Time = 0.38 (sec) , antiderivative size = 546, normalized size of antiderivative = 1.88 \[ \int \frac {\cos ^2(c+d x) \left (B \sec (c+d x)+C \sec ^2(c+d x)\right )}{(a+b \sec (c+d x))^3} \, dx=-\frac {\frac {{\left (6 \, C a^{5} b - 12 \, B a^{4} b^{2} - 5 \, C a^{3} b^{3} + 15 \, B a^{2} b^{4} + 2 \, C a b^{5} - 6 \, B b^{6}\right )} {\left (\pi \left \lfloor \frac {d x + c}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (-2 \, a + 2 \, b\right ) + \arctan \left (-\frac {a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{\sqrt {-a^{2} + b^{2}}}\right )\right )}}{{\left (a^{8} - 2 \, a^{6} b^{2} + a^{4} b^{4}\right )} \sqrt {-a^{2} + b^{2}}} + \frac {6 \, C a^{4} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 8 \, B a^{3} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 5 \, C a^{3} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 7 \, B a^{2} b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 3 \, C a^{2} b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 5 \, B a b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 2 \, C a b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 4 \, B b^{6} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 6 \, C a^{4} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 8 \, B a^{3} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 5 \, C a^{3} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 7 \, B a^{2} b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 3 \, C a^{2} b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 5 \, B a b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 2 \, C a b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 4 \, B b^{6} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{{\left (a^{7} - 2 \, a^{5} b^{2} + a^{3} b^{4}\right )} {\left (a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - a - b\right )}^{2}} - \frac {{\left (C a - 3 \, B b\right )} {\left (d x + c\right )}}{a^{4}} - \frac {2 \, B \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )} a^{3}}}{d} \]

[In]

integrate(cos(d*x+c)^2*(B*sec(d*x+c)+C*sec(d*x+c)^2)/(a+b*sec(d*x+c))^3,x, algorithm="giac")

[Out]

-((6*C*a^5*b - 12*B*a^4*b^2 - 5*C*a^3*b^3 + 15*B*a^2*b^4 + 2*C*a*b^5 - 6*B*b^6)*(pi*floor(1/2*(d*x + c)/pi + 1
/2)*sgn(-2*a + 2*b) + arctan(-(a*tan(1/2*d*x + 1/2*c) - b*tan(1/2*d*x + 1/2*c))/sqrt(-a^2 + b^2)))/((a^8 - 2*a
^6*b^2 + a^4*b^4)*sqrt(-a^2 + b^2)) + (6*C*a^4*b^2*tan(1/2*d*x + 1/2*c)^3 - 8*B*a^3*b^3*tan(1/2*d*x + 1/2*c)^3
- 5*C*a^3*b^3*tan(1/2*d*x + 1/2*c)^3 + 7*B*a^2*b^4*tan(1/2*d*x + 1/2*c)^3 - 3*C*a^2*b^4*tan(1/2*d*x + 1/2*c)^
3 + 5*B*a*b^5*tan(1/2*d*x + 1/2*c)^3 + 2*C*a*b^5*tan(1/2*d*x + 1/2*c)^3 - 4*B*b^6*tan(1/2*d*x + 1/2*c)^3 - 6*C
*a^4*b^2*tan(1/2*d*x + 1/2*c) + 8*B*a^3*b^3*tan(1/2*d*x + 1/2*c) - 5*C*a^3*b^3*tan(1/2*d*x + 1/2*c) + 7*B*a^2*
b^4*tan(1/2*d*x + 1/2*c) + 3*C*a^2*b^4*tan(1/2*d*x + 1/2*c) - 5*B*a*b^5*tan(1/2*d*x + 1/2*c) + 2*C*a*b^5*tan(1
/2*d*x + 1/2*c) - 4*B*b^6*tan(1/2*d*x + 1/2*c))/((a^7 - 2*a^5*b^2 + a^3*b^4)*(a*tan(1/2*d*x + 1/2*c)^2 - b*tan
(1/2*d*x + 1/2*c)^2 - a - b)^2) - (C*a - 3*B*b)*(d*x + c)/a^4 - 2*B*tan(1/2*d*x + 1/2*c)/((tan(1/2*d*x + 1/2*c
)^2 + 1)*a^3))/d

Mupad [B] (verification not implemented)

Time = 25.08 (sec) , antiderivative size = 5530, normalized size of antiderivative = 19.07 \[ \int \frac {\cos ^2(c+d x) \left (B \sec (c+d x)+C \sec ^2(c+d x)\right )}{(a+b \sec (c+d x))^3} \, dx=\text {Too large to display} \]

[In]

int((cos(c + d*x)^2*(B/cos(c + d*x) + C/cos(c + d*x)^2))/(a + b/cos(c + d*x))^3,x)

[Out]

((tan(c/2 + (d*x)/2)^5*(6*B*b^5 - 2*B*a^5 - 12*B*a^2*b^3 + 4*B*a^3*b^2 + C*a^2*b^3 + 6*C*a^3*b^2 - 3*B*a*b^4 +
2*B*a^4*b - 2*C*a*b^4))/((a^3*b - a^4)*(a + b)^2) + (tan(c/2 + (d*x)/2)*(2*B*a^5 + 6*B*b^5 - 12*B*a^2*b^3 - 4
*B*a^3*b^2 - C*a^2*b^3 + 6*C*a^3*b^2 + 3*B*a*b^4 + 2*B*a^4*b - 2*C*a*b^4))/((a + b)*(a^5 - 2*a^4*b + a^3*b^2))
+ (2*tan(c/2 + (d*x)/2)^3*(2*B*a^6 - 6*B*b^6 + 13*B*a^2*b^4 - 6*B*a^4*b^2 - 5*C*a^3*b^3 + 2*C*a*b^5))/(a*(a^2
*b - a^3)*(a + b)^2*(a - b)))/(d*(2*a*b + tan(c/2 + (d*x)/2)^2*(2*a*b - a^2 + 3*b^2) + tan(c/2 + (d*x)/2)^6*(a
^2 - 2*a*b + b^2) + a^2 + b^2 - tan(c/2 + (d*x)/2)^4*(2*a*b + a^2 - 3*b^2))) + (log(tan(c/2 + (d*x)/2) - 1i)*(
3*B*b - C*a)*1i)/(a^4*d) - (log(tan(c/2 + (d*x)/2) + 1i)*(B*b*3i - C*a*1i))/(a^4*d) - (b*atan(((b*((a + b)^5*(
a - b)^5)^(1/2)*((8*tan(c/2 + (d*x)/2)*(72*B^2*b^12 + 4*C^2*a^12 - 72*B^2*a*b^11 - 8*C^2*a^11*b - 288*B^2*a^2*
b^10 + 288*B^2*a^3*b^9 + 441*B^2*a^4*b^8 - 432*B^2*a^5*b^7 - 288*B^2*a^6*b^6 + 288*B^2*a^7*b^5 + 36*B^2*a^8*b^
4 - 72*B^2*a^9*b^3 + 36*B^2*a^10*b^2 + 8*C^2*a^2*b^10 - 8*C^2*a^3*b^9 - 32*C^2*a^4*b^8 + 32*C^2*a^5*b^7 + 57*C
^2*a^6*b^6 - 48*C^2*a^7*b^5 - 52*C^2*a^8*b^4 + 32*C^2*a^9*b^3 + 24*C^2*a^10*b^2 - 48*B*C*a*b^11 - 24*B*C*a^11*
b + 48*B*C*a^2*b^10 + 192*B*C*a^3*b^9 - 192*B*C*a^4*b^8 - 318*B*C*a^5*b^7 + 288*B*C*a^6*b^6 + 252*B*C*a^7*b^5
- 192*B*C*a^8*b^4 - 72*B*C*a^9*b^3 + 48*B*C*a^10*b^2))/(a^12*b + a^13 - a^6*b^7 - a^7*b^6 + 3*a^8*b^5 + 3*a^9*
b^4 - 3*a^10*b^3 - 3*a^11*b^2) + (b*((8*(4*C*a^18 + 12*B*a^8*b^10 - 6*B*a^9*b^9 - 54*B*a^10*b^8 + 24*B*a^11*b^
7 + 96*B*a^12*b^6 - 42*B*a^13*b^5 - 78*B*a^14*b^4 + 36*B*a^15*b^3 + 24*B*a^16*b^2 - 4*C*a^9*b^9 + 2*C*a^10*b^8
+ 18*C*a^11*b^7 - 4*C*a^12*b^6 - 36*C*a^13*b^5 + 6*C*a^14*b^4 + 34*C*a^15*b^3 - 8*C*a^16*b^2 - 12*B*a^17*b -
12*C*a^17*b))/(a^15*b + a^16 - a^9*b^7 - a^10*b^6 + 3*a^11*b^5 + 3*a^12*b^4 - 3*a^13*b^3 - 3*a^14*b^2) - (4*b*
tan(c/2 + (d*x)/2)*((a + b)^5*(a - b)^5)^(1/2)*(6*B*b^5 - 6*C*a^5 - 15*B*a^2*b^3 + 5*C*a^3*b^2 + 12*B*a^4*b -
2*C*a*b^4)*(8*a^17*b - 8*a^8*b^10 + 8*a^9*b^9 + 32*a^10*b^8 - 32*a^11*b^7 - 48*a^12*b^6 + 48*a^13*b^5 + 32*a^1
4*b^4 - 32*a^15*b^3 - 8*a^16*b^2))/((a^14 - a^4*b^10 + 5*a^6*b^8 - 10*a^8*b^6 + 10*a^10*b^4 - 5*a^12*b^2)*(a^1
2*b + a^13 - a^6*b^7 - a^7*b^6 + 3*a^8*b^5 + 3*a^9*b^4 - 3*a^10*b^3 - 3*a^11*b^2)))*((a + b)^5*(a - b)^5)^(1/2
)*(6*B*b^5 - 6*C*a^5 - 15*B*a^2*b^3 + 5*C*a^3*b^2 + 12*B*a^4*b - 2*C*a*b^4))/(2*(a^14 - a^4*b^10 + 5*a^6*b^8 -
10*a^8*b^6 + 10*a^10*b^4 - 5*a^12*b^2)))*(6*B*b^5 - 6*C*a^5 - 15*B*a^2*b^3 + 5*C*a^3*b^2 + 12*B*a^4*b - 2*C*a
*b^4)*1i)/(2*(a^14 - a^4*b^10 + 5*a^6*b^8 - 10*a^8*b^6 + 10*a^10*b^4 - 5*a^12*b^2)) + (b*((a + b)^5*(a - b)^5)
^(1/2)*((8*tan(c/2 + (d*x)/2)*(72*B^2*b^12 + 4*C^2*a^12 - 72*B^2*a*b^11 - 8*C^2*a^11*b - 288*B^2*a^2*b^10 + 28
8*B^2*a^3*b^9 + 441*B^2*a^4*b^8 - 432*B^2*a^5*b^7 - 288*B^2*a^6*b^6 + 288*B^2*a^7*b^5 + 36*B^2*a^8*b^4 - 72*B^
2*a^9*b^3 + 36*B^2*a^10*b^2 + 8*C^2*a^2*b^10 - 8*C^2*a^3*b^9 - 32*C^2*a^4*b^8 + 32*C^2*a^5*b^7 + 57*C^2*a^6*b^
6 - 48*C^2*a^7*b^5 - 52*C^2*a^8*b^4 + 32*C^2*a^9*b^3 + 24*C^2*a^10*b^2 - 48*B*C*a*b^11 - 24*B*C*a^11*b + 48*B*
C*a^2*b^10 + 192*B*C*a^3*b^9 - 192*B*C*a^4*b^8 - 318*B*C*a^5*b^7 + 288*B*C*a^6*b^6 + 252*B*C*a^7*b^5 - 192*B*C
*a^8*b^4 - 72*B*C*a^9*b^3 + 48*B*C*a^10*b^2))/(a^12*b + a^13 - a^6*b^7 - a^7*b^6 + 3*a^8*b^5 + 3*a^9*b^4 - 3*a
^10*b^3 - 3*a^11*b^2) - (b*((8*(4*C*a^18 + 12*B*a^8*b^10 - 6*B*a^9*b^9 - 54*B*a^10*b^8 + 24*B*a^11*b^7 + 96*B*
a^12*b^6 - 42*B*a^13*b^5 - 78*B*a^14*b^4 + 36*B*a^15*b^3 + 24*B*a^16*b^2 - 4*C*a^9*b^9 + 2*C*a^10*b^8 + 18*C*a
^11*b^7 - 4*C*a^12*b^6 - 36*C*a^13*b^5 + 6*C*a^14*b^4 + 34*C*a^15*b^3 - 8*C*a^16*b^2 - 12*B*a^17*b - 12*C*a^17
*b))/(a^15*b + a^16 - a^9*b^7 - a^10*b^6 + 3*a^11*b^5 + 3*a^12*b^4 - 3*a^13*b^3 - 3*a^14*b^2) + (4*b*tan(c/2 +
(d*x)/2)*((a + b)^5*(a - b)^5)^(1/2)*(6*B*b^5 - 6*C*a^5 - 15*B*a^2*b^3 + 5*C*a^3*b^2 + 12*B*a^4*b - 2*C*a*b^4
)*(8*a^17*b - 8*a^8*b^10 + 8*a^9*b^9 + 32*a^10*b^8 - 32*a^11*b^7 - 48*a^12*b^6 + 48*a^13*b^5 + 32*a^14*b^4 - 3
2*a^15*b^3 - 8*a^16*b^2))/((a^14 - a^4*b^10 + 5*a^6*b^8 - 10*a^8*b^6 + 10*a^10*b^4 - 5*a^12*b^2)*(a^12*b + a^1
3 - a^6*b^7 - a^7*b^6 + 3*a^8*b^5 + 3*a^9*b^4 - 3*a^10*b^3 - 3*a^11*b^2)))*((a + b)^5*(a - b)^5)^(1/2)*(6*B*b^
5 - 6*C*a^5 - 15*B*a^2*b^3 + 5*C*a^3*b^2 + 12*B*a^4*b - 2*C*a*b^4))/(2*(a^14 - a^4*b^10 + 5*a^6*b^8 - 10*a^8*b
^6 + 10*a^10*b^4 - 5*a^12*b^2)))*(6*B*b^5 - 6*C*a^5 - 15*B*a^2*b^3 + 5*C*a^3*b^2 + 12*B*a^4*b - 2*C*a*b^4)*1i)
/(2*(a^14 - a^4*b^10 + 5*a^6*b^8 - 10*a^8*b^6 + 10*a^10*b^4 - 5*a^12*b^2)))/((16*(108*B^3*b^12 - 54*B^3*a*b^11
- 12*C^3*a^11*b - 486*B^3*a^2*b^10 + 243*B^3*a^3*b^9 + 864*B^3*a^4*b^8 - 378*B^3*a^5*b^7 - 702*B^3*a^6*b^6 +
216*B^3*a^7*b^5 + 216*B^3*a^8*b^4 - 4*C^3*a^3*b^9 + 2*C^3*a^4*b^8 + 18*C^3*a^5*b^7 - 13*C^3*a^6*b^6 - 36*C^3*a
^7*b^5 + 26*C^3*a^8*b^4 + 34*C^3*a^9*b^3 - 24*C^3*a^10*b^2 - 108*B^2*C*a*b^11 + 36*B*C^2*a^2*b^10 - 18*B*C^2*a
^3*b^9 - 162*B*C^2*a^4*b^8 + 105*B*C^2*a^5*b^7 + 312*B*C^2*a^6*b^6 - 198*B*C^2*a^7*b^5 - 282*B*C^2*a^8*b^4 + 1
56*B*C^2*a^9*b^3 + 96*B*C^2*a^10*b^2 + 54*B^2*C*a^2*b^10 + 486*B^2*C*a^3*b^9 - 279*B^2*C*a^4*b^8 - 900*B^2*C*a
^5*b^7 + 486*B^2*C*a^6*b^6 + 774*B^2*C*a^7*b^5 - 324*B^2*C*a^8*b^4 - 252*B^2*C*a^9*b^3))/(a^15*b + a^16 - a^9*
b^7 - a^10*b^6 + 3*a^11*b^5 + 3*a^12*b^4 - 3*a^13*b^3 - 3*a^14*b^2) + (b*((a + b)^5*(a - b)^5)^(1/2)*((8*tan(c
/2 + (d*x)/2)*(72*B^2*b^12 + 4*C^2*a^12 - 72*B^2*a*b^11 - 8*C^2*a^11*b - 288*B^2*a^2*b^10 + 288*B^2*a^3*b^9 +
441*B^2*a^4*b^8 - 432*B^2*a^5*b^7 - 288*B^2*a^6*b^6 + 288*B^2*a^7*b^5 + 36*B^2*a^8*b^4 - 72*B^2*a^9*b^3 + 36*B
^2*a^10*b^2 + 8*C^2*a^2*b^10 - 8*C^2*a^3*b^9 - 32*C^2*a^4*b^8 + 32*C^2*a^5*b^7 + 57*C^2*a^6*b^6 - 48*C^2*a^7*b
^5 - 52*C^2*a^8*b^4 + 32*C^2*a^9*b^3 + 24*C^2*a^10*b^2 - 48*B*C*a*b^11 - 24*B*C*a^11*b + 48*B*C*a^2*b^10 + 192
*B*C*a^3*b^9 - 192*B*C*a^4*b^8 - 318*B*C*a^5*b^7 + 288*B*C*a^6*b^6 + 252*B*C*a^7*b^5 - 192*B*C*a^8*b^4 - 72*B*
C*a^9*b^3 + 48*B*C*a^10*b^2))/(a^12*b + a^13 - a^6*b^7 - a^7*b^6 + 3*a^8*b^5 + 3*a^9*b^4 - 3*a^10*b^3 - 3*a^11
*b^2) + (b*((8*(4*C*a^18 + 12*B*a^8*b^10 - 6*B*a^9*b^9 - 54*B*a^10*b^8 + 24*B*a^11*b^7 + 96*B*a^12*b^6 - 42*B*
a^13*b^5 - 78*B*a^14*b^4 + 36*B*a^15*b^3 + 24*B*a^16*b^2 - 4*C*a^9*b^9 + 2*C*a^10*b^8 + 18*C*a^11*b^7 - 4*C*a^
12*b^6 - 36*C*a^13*b^5 + 6*C*a^14*b^4 + 34*C*a^15*b^3 - 8*C*a^16*b^2 - 12*B*a^17*b - 12*C*a^17*b))/(a^15*b + a
^16 - a^9*b^7 - a^10*b^6 + 3*a^11*b^5 + 3*a^12*b^4 - 3*a^13*b^3 - 3*a^14*b^2) - (4*b*tan(c/2 + (d*x)/2)*((a +
b)^5*(a - b)^5)^(1/2)*(6*B*b^5 - 6*C*a^5 - 15*B*a^2*b^3 + 5*C*a^3*b^2 + 12*B*a^4*b - 2*C*a*b^4)*(8*a^17*b - 8*
a^8*b^10 + 8*a^9*b^9 + 32*a^10*b^8 - 32*a^11*b^7 - 48*a^12*b^6 + 48*a^13*b^5 + 32*a^14*b^4 - 32*a^15*b^3 - 8*a
^16*b^2))/((a^14 - a^4*b^10 + 5*a^6*b^8 - 10*a^8*b^6 + 10*a^10*b^4 - 5*a^12*b^2)*(a^12*b + a^13 - a^6*b^7 - a^
7*b^6 + 3*a^8*b^5 + 3*a^9*b^4 - 3*a^10*b^3 - 3*a^11*b^2)))*((a + b)^5*(a - b)^5)^(1/2)*(6*B*b^5 - 6*C*a^5 - 15
*B*a^2*b^3 + 5*C*a^3*b^2 + 12*B*a^4*b - 2*C*a*b^4))/(2*(a^14 - a^4*b^10 + 5*a^6*b^8 - 10*a^8*b^6 + 10*a^10*b^4
- 5*a^12*b^2)))*(6*B*b^5 - 6*C*a^5 - 15*B*a^2*b^3 + 5*C*a^3*b^2 + 12*B*a^4*b - 2*C*a*b^4))/(2*(a^14 - a^4*b^1
0 + 5*a^6*b^8 - 10*a^8*b^6 + 10*a^10*b^4 - 5*a^12*b^2)) - (b*((a + b)^5*(a - b)^5)^(1/2)*((8*tan(c/2 + (d*x)/2
)*(72*B^2*b^12 + 4*C^2*a^12 - 72*B^2*a*b^11 - 8*C^2*a^11*b - 288*B^2*a^2*b^10 + 288*B^2*a^3*b^9 + 441*B^2*a^4*
b^8 - 432*B^2*a^5*b^7 - 288*B^2*a^6*b^6 + 288*B^2*a^7*b^5 + 36*B^2*a^8*b^4 - 72*B^2*a^9*b^3 + 36*B^2*a^10*b^2
+ 8*C^2*a^2*b^10 - 8*C^2*a^3*b^9 - 32*C^2*a^4*b^8 + 32*C^2*a^5*b^7 + 57*C^2*a^6*b^6 - 48*C^2*a^7*b^5 - 52*C^2*
a^8*b^4 + 32*C^2*a^9*b^3 + 24*C^2*a^10*b^2 - 48*B*C*a*b^11 - 24*B*C*a^11*b + 48*B*C*a^2*b^10 + 192*B*C*a^3*b^9
- 192*B*C*a^4*b^8 - 318*B*C*a^5*b^7 + 288*B*C*a^6*b^6 + 252*B*C*a^7*b^5 - 192*B*C*a^8*b^4 - 72*B*C*a^9*b^3 +
48*B*C*a^10*b^2))/(a^12*b + a^13 - a^6*b^7 - a^7*b^6 + 3*a^8*b^5 + 3*a^9*b^4 - 3*a^10*b^3 - 3*a^11*b^2) - (b*(
(8*(4*C*a^18 + 12*B*a^8*b^10 - 6*B*a^9*b^9 - 54*B*a^10*b^8 + 24*B*a^11*b^7 + 96*B*a^12*b^6 - 42*B*a^13*b^5 - 7
8*B*a^14*b^4 + 36*B*a^15*b^3 + 24*B*a^16*b^2 - 4*C*a^9*b^9 + 2*C*a^10*b^8 + 18*C*a^11*b^7 - 4*C*a^12*b^6 - 36*
C*a^13*b^5 + 6*C*a^14*b^4 + 34*C*a^15*b^3 - 8*C*a^16*b^2 - 12*B*a^17*b - 12*C*a^17*b))/(a^15*b + a^16 - a^9*b^
7 - a^10*b^6 + 3*a^11*b^5 + 3*a^12*b^4 - 3*a^13*b^3 - 3*a^14*b^2) + (4*b*tan(c/2 + (d*x)/2)*((a + b)^5*(a - b)
^5)^(1/2)*(6*B*b^5 - 6*C*a^5 - 15*B*a^2*b^3 + 5*C*a^3*b^2 + 12*B*a^4*b - 2*C*a*b^4)*(8*a^17*b - 8*a^8*b^10 + 8
*a^9*b^9 + 32*a^10*b^8 - 32*a^11*b^7 - 48*a^12*b^6 + 48*a^13*b^5 + 32*a^14*b^4 - 32*a^15*b^3 - 8*a^16*b^2))/((
a^14 - a^4*b^10 + 5*a^6*b^8 - 10*a^8*b^6 + 10*a^10*b^4 - 5*a^12*b^2)*(a^12*b + a^13 - a^6*b^7 - a^7*b^6 + 3*a^
8*b^5 + 3*a^9*b^4 - 3*a^10*b^3 - 3*a^11*b^2)))*((a + b)^5*(a - b)^5)^(1/2)*(6*B*b^5 - 6*C*a^5 - 15*B*a^2*b^3 +
5*C*a^3*b^2 + 12*B*a^4*b - 2*C*a*b^4))/(2*(a^14 - a^4*b^10 + 5*a^6*b^8 - 10*a^8*b^6 + 10*a^10*b^4 - 5*a^12*b^
2)))*(6*B*b^5 - 6*C*a^5 - 15*B*a^2*b^3 + 5*C*a^3*b^2 + 12*B*a^4*b - 2*C*a*b^4))/(2*(a^14 - a^4*b^10 + 5*a^6*b^
8 - 10*a^8*b^6 + 10*a^10*b^4 - 5*a^12*b^2))))*((a + b)^5*(a - b)^5)^(1/2)*(6*B*b^5 - 6*C*a^5 - 15*B*a^2*b^3 +
5*C*a^3*b^2 + 12*B*a^4*b - 2*C*a*b^4)*1i)/(d*(a^14 - a^4*b^10 + 5*a^6*b^8 - 10*a^8*b^6 + 10*a^10*b^4 - 5*a^12*
b^2))